Introduction:
When it comes to managing stacks of widgets in Flutter, the IndexedStack widget stands out as a versatile solution. This blog post dives into the capabilities of the IndexedStack widget, exploring its attributes and demonstrating how it can be effectively used to toggle between multiple child widgets with ease.
What is IndexedStack Widget?
The IndexedStack widget in Flutter is designed to display only one child at a time, from a list of children, based on the index provided. This makes it particularly useful for scenarios where you want to toggle between different widgets without rebuilding the entire widget tree.
Attributes of IndexedStack:
index (required): The index of the child to be displayed. The child at this index will be visible, while others will be hidden.
index: 0,
alignment: The alignment of the children within the stack.
alignment: Alignment.center,
sizing: Determines how the stack should size itself.
dartCopy codesizing: StackFit.loose,
Example Usage:
Let's create an example where we use IndexedStack to toggle between different widgets based on a selected index.
IndexedStack(
index: currentIndex,
alignment: Alignment.center,
sizing: StackFit.loose,
children: [
Container(
color: Colors.blue,
child: Center(child: Text('Widget 1')),
),
Container(
color: Colors.green,
child: Center(child: Text('Widget 2')),
),
Container(
color: Colors.orange,
child: Center(child: Text('Widget 3')),
),
],
)
In this example, we have an IndexedStack containing three containers with different colors and text. The currentIndex determines which container is currently visible.